提问者：肥婆大晒  |  浏览 次  |  提问时间：2017-01-12  |  回答数量：6

求Pn(x)=a0+a1*x+a28x*x+a3*x*x*x+a4x*x*x*x+...an*x（n次方）#include \"stdio.h\"#include \"conio.h\"#define X 3.0double P(double p,float a,int i) { int k,j; k=i; for(j=0;j<=k;j++)p=a*X; p+=p; returnp; }main(){int i,n,N;float a;double p=0;N=0;printf(\"enter n:\");scanf(\"%d\",&n);printf(\"\\n\");for(i=0;i<=n;i++){ printf(\"enter a%d:\",i); scanf(\"%f\",&a); p=P(p,a,i); N++;}printf(\"\\nP%d(%d)=%lf\\n循环体执行次数:%d\",n,X,p,N);getch();}